1/2(x^2+3)-2=10

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Solution for 1/2(x^2+3)-2=10 equation:


x in (-oo:+oo)

(1/2)*(x^2+3)-2 = 10 // - 10

(1/2)*(x^2+3)-10-2 = 0

1/2*(x^2+3)-10-2 = 0

1/2*(x^2+3)-10-2 = 0

1/2*x^2-17/2-2 = 0

1/2*x^2-21/2 = 0

1/2*x^2-21/2 = 0

1/2*x^2 = 21/2 // : 1/2

x^2 = 21

x^2 = 21 // ^ 1/2

abs(x) = 21^(1/2)

x = 21^(1/2) or x = -21^(1/2)

x in { 21^(1/2), -21^(1/2) }

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